Chapter 7 Mensuration Class 10 Maharashtra Board TextBook Solution
Practice set 7.1 | Q 9 | Page 145
In the figure 7.12, a cylindrical
wrapper of flat tablets is shown.
The radius of a tablet is 7 mm and
its thickness is 5 mm. How many
such tablets are wrapped in the
wrapper ?
Answer:-
Radius of a tablet, r = 7 mm Thickness of a tablet, h = 5 mm Radius of cylindrical wrapper, R = 7 mm Height of wrapper (H) = 10 cm = 100 mm Let n be the number of tablets wrapped in the wrapper.
n = Volume of the cylindrical wrapper / Volume of each tablet n = (πR^2H) / (πr^2h) n = (7^2 x 100) / (7^2 x 5) = 20
Thus, 20 tablets are wrapped in the wrapper.
Solution
$$Radius space of space a space tablet, r = 7 space mm$$
$$Thickness space of space a space tablet, h = 5 space mm$$
$$Radius space of space cylindrical space wrapper, R =$$
$$frac{14}{2} = 7 space mm$$
$$Height space of space wrapper space (H) = 10 space cm = 10 times 10 space mm = 100 space mm$$
Let $$n$$ be the number of tablets wrapped in the wrapper.
$$n = frac{text{Volume of the cylindrical wrapper}}{text{Volume of each tablet}}$$
$$Rightarrow n = frac{pi R^2 H}{pi r^2 h}$$
$$Rightarrow n = frac{(7)^2 times 100}{(7)^2 times 5} = 20$$
Thus, 20 tablets are wrapped in the wrapper.
Chapter 7 Mensuration Textbook Solution 7.1
Practice set 7.1
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