Find the distances between the following points.
(ii) P(-6, -3), Q(-1, 9)

6. Find the distances between the following points.

(ii) P(-6, -3), Q(-1, 9)

Answer:-

P(–6, –3), Q(–1, 9)

[PQ = sqrt{left( – 6 – left( – 1 right) right)^2 + left( – 3 – 9 right)^2}]

[ = sqrt{25 + 144}]

[ = sqrt{169}]

[ = 13]

Explanation:-

Given two points P(-6, -3) and Q(-1, 9), we can find the distance between them using the distance formula.

The distance formula is:

distance = sqrt((x2 – x1)^2 + (y2 – y1)^2)

Substituting the values of the given points, we get:

PQ = sqrt((-1 – (-6))^2 + (9 – (-3))^2)

PQ = sqrt((5)^2 + (12)^2)

PQ = sqrt(25 + 144)

PQ = sqrt(169)

PQ = 13

Therefore, the distance between the points P(-6, -3) and Q(-1, 9) is 13 units. Hope you like it

Chapter 5. Co-ordinate Geometry – Problem set 5 (Page 122)