Husharmulga.com Class 8 Ganita Prakash Chapter 4 :- Quadrilateral Class 8 Ganita Prakash

Chapter 4 :- Quadrilateral Class 8 Ganita Prakash

FIGURE IT OUT

  1. Find all the other angles inside the following rectangles.

(i) Rectangle ABCD

Given:
ABCD is a rectangle.
The diagonals AC and BD intersect.
∠CAB = 30°.

Solution:

Since ABCD is a rectangle,

∠DAB = 90°

Therefore,

∠DAC + ∠CAB = 90°

∠DAC + 30° = 90°

∴ ∠DAC = 60°

Since opposite sides of a rectangle are parallel,

AB ∥ DC

Therefore,

∠DCA = ∠CAB = 30°

Since ∠DCB = 90°,

∠ACB = 90° − 30°

∴ ∠ACB = 60°

Similarly, for diagonal BD,

∠ABD = 30°

and

∠ADB = 60°

Therefore, the angles at the four corners formed by the diagonals are:

∠CAB = 30°
∠DAC = 60°
∠DCA = 30°
∠ACB = 60°
∠ABD = 30°
∠DBC = 60°
∠ADB = 60°
∠BDC = 30°

Now, let the diagonals AC and BD intersect at O.

The angle between the diagonals is:

∠AOB = 60°

Vertically opposite angles are equal.

Therefore,

∠COD = 60°

The adjacent angles form a straight angle.

Therefore,

∠AOD = 180° − 60°
∠AOD = 120°

Similarly,

∠BOC = 120°

Hence, the four angles at the intersection of the diagonals are:

60°, 120°, 60°, 120°

Answer for (i):

The angles formed by the diagonals at the corners are 30° and 60°.

The angles at the intersection of the diagonals are:

60°, 120°, 60°, 120°

(ii) Rectangle PQRS

Given:
PQRS is a rectangle.
The diagonals PR and QS intersect at O.
∠QOR = 110°.

Solution:

Since ∠QOR = 110°,

and vertically opposite angles are equal,

∠POS = 110°

The adjacent angles form a straight angle.

Therefore,

∠QOR + ∠QOP = 180°

110° + ∠QOP = 180°

∴ ∠QOP = 70°

Similarly,

∠ROS = 70°

Therefore, the four angles at the intersection of the diagonals are:

110°, 70°, 110°, 70°

Now, since the diagonals are symmetrically placed in the rectangle, each diagonal makes half of the 110° angle with the vertical direction.

Therefore,

110° ÷ 2 = 55°

Thus, each diagonal makes an angle of 55° with the vertical side.

Since the angle of a rectangle is 90°,

Angle with the horizontal side = 90° − 55°

= 35°

Therefore, the diagonal divides each corner of the rectangle into:

35° and 55°

Answer for (ii):

The angles formed by the diagonals at each corner are:

35° and 55°

The angles at the intersection of the diagonals are:

110°, 70°, 110°, 70°

FINAL ANSWERS

(i) Rectangle ABCD

Corner angles formed by the diagonals:
30°, 60°, 30°, 60°, 30°, 60°, 60°, 30°

Angles at the intersection:
60°, 120°, 60°, 120°

(ii) Rectangle PQRS

Corner angles formed by the diagonals:
35° and 55°

Angles at the intersection:
110°, 70°, 110°, 70°

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