Chapter 7 Mensuration Class 10 Maharashtra Board TextBook Solution
Practice set 7.2 | Q 1| Page 148
The radii of two circular ends of frustum shape bucket are 14 cm and 7 cm. Height of the bucket is 30 cm. How many liters of water it can hold ? (1 litre = 1000 cm3)
Answer:-
Radius of one circular end, r1 = 14 cm
Radius of other circular end, r2 = 7 cm
Height of the bucket, h = 30 cm
Therefore, Volume of water in the bucket = Volume of frustum of cone = (1/3) * π * h * (r1^2 + r1r2 + r2^2)
= (1/3) * (22/7) * 30 * (14^2 + 147 + 7^2)
= (1/3) * (22/7) * 30 * 343
= 10780 cm^3
= 10780/1000
= 10.780 L
Thus, the bucket can hold 10.780 litres of water.
Solution
$$Radius of one circular end, r_1=14 cm$$
$$Radius of other circular end, r_2=7 cm$$
$$Height of the bucket, h=30 cm$$
Therefore, Volume of water in the bucket = Volume of frustum of cone
$$= frac{1}{3} times pi times h times (r_1^2 + r_1r_2 + r_2^2)$$
$$= frac{1}{3} times frac{22}{7} times 30 times (14^2 + 14 times 7 + 7^2)$$
$$= frac{1}{3} times frac{22}{7} times 30 times 343$$
$$= 10780 cm^3$$
$$= frac{10780}{1000}$$
$$= 10.780 L$$
Thus, the bucket can hold 10.780 litres of water.
Chapter 7 Mensuration Textbook Solution 7.2
Practice set 7.1
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