Distance of point (-3,4) from the origin is ...... . (A) 7 (B) 1 (C) 5 (D) -5
(3) Distance of point (-3,4) from the origin is …… .
(A) 7 (B) 1 (C) 5 (D) -5
Answer:-
5
Explanation:
Let the given point be P(–3, 4).
Distance of P(–3, 4) from the origin O(0, 0) is
\[\sqrt{((0 - (-3))^2 + (0 - 4)^2}\]
=\[\sqrt{(9 + 16)}\]
=\[\sqrt(25)\]`
Explanation:-
To find the distance between the given point P(-3, 4) and the origin O(0, 0), we can use the distance formula, which is given by:
d = √[(x2 – x1)^2 + (y2 – y1)^2]
Here, we have x1 = 0, y1 = 0, x2 = -3, and y2 = 4. Plugging in these values, we get:
d = √[(-3 – 0)^2 + (4 – 0)^2] = √[9 + 16] = √25 = 5
Therefore, the distance between the point P(-3, 4) and the origin O(0, 0) is 5 units.
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Chapter 5. Co-ordinate Geometry – Problem Set 5 (Page 122)