Chapter 4 – Geometric Construction – Text Book Solution
Practice set 4.1 |Q 1 | P 96
Δ ABC ~ Δ LMN. In Δ ABC, AB = 5.5 cm, BC = 6 cm, CA = 4.5 cm. If MN = 4.8 cm, then construct Δ ABC and Δ LMN such that BC/MN = 5/4
Construct ∆ABC such that AB = 5.5 cm, BC = 6 cm and CA = 4.5 cm.
∆ABC and ∆LMN are similar.
Therefore, their corresponding sides are proportional.
\[\therefore \frac{AB}{LM} = \frac{BC}{MN} = \frac{CA}{NL} = \frac{5}{4}\]
\[\Rightarrow \frac{5 . 5}{LM} = \frac{6}{MN} = \frac{4 . 5}{NL} = \frac{5}{4}\]
\[\Rightarrow LM = \frac{4}{5} \times 5 . 5 = 4 . 4 \text{ cm}, MN = \frac{4}{5} \times 6 = 4 . 8\text{ cm} , NL = \frac{4}{5} \times 4 . 5 = 3 . 6 \] cm
Now, construct ∆LMN such that LM = 4.4 cm, MN = 4.8 cm and NL = 3.6 cm.
Chapter 4 – Geometric Construction – Text Book Solution
Practice set 4.1 |Q 1 | P 96
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