Prove that:cotθ + tanθ = cosecθ secθ
Chapter 6 – Trigonometry – Text Book Solution
Practice Set 6.1| Q 6.5 | Page 132
Prove that:cotθ + tanθ = cosecθ secθ
Solution
We can start by using the definitions of cotangent, tangent, cosecant, and secant:
cotθ + tanθ
= cosθ/sinθ + sinθ/cosθ
= (cos²θ + sin²θ)/(sinθ cosθ)
= 1/(sinθ cosθ)
= (1/sinθ) * (1/cosθ)
= cosecθ * secθ
Therefore, we have shown that cotθ + tanθ = cosecθ secθ.
Explanation:-
We will prove that cotθ + tanθ = cosecθ secθ using trigonometric identities.
We know that cotθ = cosθ / sinθ and tanθ = sinθ / cosθ
Substituting these values in cotθ + tanθ, we get:
cotθ + tanθ = cosθ / sinθ + sinθ / cosθ
To simplify this expression, we can take the common denominator, which is sinθ cosθ.
cotθ + tanθ = (cos²θ + sin²θ) / (sinθ cosθ)
Using the identity cos²θ + sin²θ = 1, we get:
cotθ + tanθ = 1 / (sinθ cosθ)
Recall that cosecθ = 1 / sinθ and secθ = 1 / cosθ. Substituting these values, we get:
cotθ + tanθ = (1 / sinθ) x (1 / cosθ)
cotθ + tanθ = cosecθ secθ
Hence, we have proved that cotθ + tanθ = cosecθ secθ using trigonometric identities.
Chapter 6 – Trigonometry – Text Book Solution
Practice set 6.1 |Q 6.5| P 132
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