Hushar Mulga
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Prove that:cotθ + tanθ = cosecθ secθ

Chapter 6 – Trigonometry – Text Book Solution

Practice Set 6.1| Q 6.5 | Page 132

Prove that:cotθ + tanθ = cosecθ secθ

Solution

We can start by using the definitions of cotangent, tangent, cosecant, and secant:

cotθ + tanθ

= cosθ/sinθ + sinθ/cosθ

= (cos²θ + sin²θ)/(sinθ cosθ)

= 1/(sinθ cosθ)

= (1/sinθ) * (1/cosθ)

= cosecθ * secθ

Therefore, we have shown that cotθ + tanθ = cosecθ secθ.

Explanation:-

We will prove that cotθ + tanθ = cosecθ secθ using trigonometric identities.

We know that cotθ = cosθ / sinθ and tanθ = sinθ / cosθ

Substituting these values in cotθ + tanθ, we get:

cotθ + tanθ = cosθ / sinθ + sinθ / cosθ

To simplify this expression, we can take the common denominator, which is sinθ cosθ.

cotθ + tanθ = (cos²θ + sin²θ) / (sinθ cosθ)

Using the identity cos²θ + sin²θ = 1, we get:

cotθ + tanθ = 1 / (sinθ cosθ)

Recall that cosecθ = 1 / sinθ and secθ = 1 / cosθ. Substituting these values, we get:

cotθ + tanθ = (1 / sinθ) x (1 / cosθ)

cotθ + tanθ = cosecθ secθ

Hence, we have proved that cotθ + tanθ = cosecθ secθ using trigonometric identities.

 

Chapter 6 – Trigonometry – Text Book Solution

Practice set 6.1 |Q 6.5| P 132

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