Chapter 4 – Geometric Construction – Text Book Solution
Practice Set 4.1 | Q 2 | Page 96
∆PQR ~ ∆LTR. In ∆PQR, PQ = 4.2 cm, QR = 5.4 cm, PR = 4.8 cm. Construct ∆PQR and ∆LTR, such that `”PQ”/”LT” = 3/4`
Solution:-
Steps of construction:
- Draw a triangle PQR, with PQ = 4.2 cm, QR = 5.4 cm and PR = 4.8 cm, choosing QR = 5.4 cm as base.
2)Below QR, draw an acute angle ∠QRX
3 Mark four points R1, R2, R3 and R4 on RX, such that RR1 = R1R2 = R2R3 = R3R4. [As ratio is 4:3, we choose 4 points]
4 Join QR4 and Draw TR3 || QR4
5 Draw LT || PQ.
Chapter 4 – Geometric Construction – Text Book Solution
Practice set 4.1 |Q 1 | P 96
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