In the given figure, ∠ABC = 75°, ∠EDC = 75° state...........
Practice Set 1.3 | Q 1 | Page 21
In the given figure, ∠ABC = 75°, ∠EDC = 75° state which two triangles are similar and by which test? Also write the similarity of these two triangles by a proper one to one correspondence.
Given:
∠ABC = 75°, ∠EDC = 75°
Now, in △ABC and △EDC
∠ABC = ∠EDC = 75° (Given)
∠C = ∠C (Common)
By AA test of similarity
△ABC ∼ △EDC
Answer:-
Given: ∠ABC = 75°, ∠EDC = 75°
To prove: △ABC ∼ △EDC by AA test of similarity.
Explanation:
- In △ABC and △EDC, ∠ABC = ∠EDC = 75° (Given)
- Also, ∠C is common to both triangles.
- Therefore, by the Angle-Angle (AA) test of similarity, △ABC is similar to △EDC.
One possible correspondence of the vertices of the two triangles is: A ↔ E B ↔ D C ↔ C
Thus, the two triangles are similar because they have two corresponding angles that are equal.
Chapter 1. Similarity- Practice Set 1.3 – Page 21
Click Here for All Textbook Soutions of Chapter 1: Similarity