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A kite is flying at a height of 60 m above the ground.........

Chapter 6 – Trigonometry – Text Book Solution

Practice Set 6.3| Q 6| Page 137

A kite is flying at a height of 60 m above the ground. The string attached to the kite is tied at the ground. It makes an angle of 60° with the ground. Assuming that the string is straight, find the length of the string. ( 3 =1.73)

Solution

Let’s denote the length of the string as “l”. We can draw a right-angled triangle, where the height of the triangle is the height of the kite above the ground (which is given as 60 meters), the base of the triangle is the distance from the point where the string is tied to the kite (which is what we’re trying to find), and the hypotenuse is the length of the string.

From the triangle, we can see that:

sin(60°) = 60/l

sin(60°) is equal to √3/2, so we can simplify the equation to:

√3/2 = 60/l

Multiplying both sides by 2, we get:

√3 = 120/l

Squaring both sides, we get:

3 = (120/l)^2

Taking the square root of both sides, we get:

√3 = 120/l

Dividing both sides by √3, we get:

l = 120/√3

We can rationalize the denominator by multiplying both the numerator and denominator by √3:

l = (120/√3) x (√3/√3) = 40√3

Therefore, the length of the string is approximately 40√3 meters.

Chapter 6 – Trigonometry – Text Book Solution

Practice set 6.2 |Q 6| P 137

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