In the given figure, ray PQ touches the circle at point Q. PQ = 12, PR = 8, find PS and RS
Chapter 3 – Circle – Text Book Solution
Practice Set 3.5 | Q 1 | Page 82
In the given figure, ray PQ touches the circle at point Q. PQ = 12, PR = 8, find PS and RS
solution
Using tangent secant segments theorem, we have
PQ2 = PR × PS
⇒ (12)2 = 8 × PS
⇒ PS = \[\frac{144}{8}\] = 18 units
∴ RS = PS − PR = 18 − 8 = 10 units
Explanation:-
Using the tangent-secant segments theorem, we have:
PQ^2 = PR x PS
So, substituting the given values, we get:
(12)^2 = 8 x PS
Simplifying the equation, we get:
PS = 144/8 = 18 units
Therefore, RS can be found by subtracting PR from PS:
RS = PS – PR = 18 – 8 = 10 units.
Chapter 3 – Circle – Text Book Solution
Practice set 3.5 | Q 1 | Page 82
Click Here to see All the Textbook solution of Circle