Hushar Mulga
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Prove that, any rectangle is a cyclic quadrilateral

Chapter 3 – Circle – Text Book Solution

Practice Set 3.4 | Q 5 | Page 73

Prove that, any rectangle is a cyclic quadrilateral

solution
Given: ▢ABCD is a rectangle.

To prove: ▢ABCD is a cyclic quadrilateral

Proof:

▢ABCD is a rectangle.                ....[Given]

∴ ∠A = ∠B = ∠C = ∠D = 90°     ....[Angles of a rectangle]

Now, ∠A + ∠C = 90° + 90° 

∴ ∠A + ∠C = 180°

We know, if a pair of opposite angles of a quadrilateral is supplementary, then the quadrilateral is cyclic.

∴ ▢ABCD is a cyclic quadrilateral   ......[Converse of cyclic quadrilateral theorem]

So, any rectangle is a cyclic quadrilateral.

Explanation:- 

Given: ▢ABCD is a rectangle.

To prove: ▢ABCD is a cyclic quadrilateral

Proof:

▢ABCD is a rectangle. ….[Given] Therefore, the angles of the rectangle satisfy: ∠A = ∠B = ∠C = ∠D = 90° ….[Angles of a rectangle]

Now, ∠A + ∠C = 90° + 90° Therefore, ∠A + ∠C = 180°

We know that if a pair of opposite angles of a quadrilateral is supplementary, then the quadrilateral is cyclic.

Therefore, ▢ABCD is a cyclic quadrilateral ….[Converse of cyclic quadrilateral theorem]

Hence, any rectangle is a cyclic quadrilateral.

Chapter 3 – Circle – Text Book Solution

Practice set 3.4  | Q 5 | Page 73

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